SOLUTION: Hotel A and hotel B had a total of 6,500 guests. After 3/4 of the guests in Hotel A and 3/5 of the guests in hotel B checked out, they were 260 more guests in hotel B there in hote

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Hotel A and hotel B had a total of 6,500 guests. After 3/4 of the guests in Hotel A and 3/5 of the guests in hotel B checked out, they were 260 more guests in hotel B there in hote      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1122050: Hotel A and hotel B had a total of 6,500 guests. After 3/4 of the guests in Hotel A and 3/5 of the guests in hotel B checked out, they were 260 more guests in hotel B there in hotel A. How many more guests did hotel A have at first?
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
a      + b = 6500,       (1)

-%281%2F4%29a + %282%2F5%29b = 260.    (2)


Solve the system for "a" and "b".  Then compute  a-b.