SOLUTION: In the lab, Lashonda has two solutions that contain alcohol and is mixing them with each other. She uses 300 milliliters less of Solution A than Solution B. Solution A is 19%

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: In the lab, Lashonda has two solutions that contain alcohol and is mixing them with each other. She uses 300 milliliters less of Solution A than Solution B. Solution A is 19%      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1122001: In the lab, Lashonda has two solutions that contain alcohol and is mixing them with each other. She uses
300
milliliters less of Solution A than Solution B. Solution A is
19%
alcohol and Solution B is
12%
alcohol. How many milliliters of Solution A does she use, if the resulting mixture has
377
milliliters of pure alcohol?

Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x = "How many milliliters of Solution A does she use", in mL.

Then the amount of the solution B is (x+300) mL.


Then your equation is


"pure alcohol" + "pure alcohol" = "total pure alcohol"


0.19x          +  0.12*(x+300)  = 377.


Simplify and solve for x:


0.19x + 0.12x + 36 = 377


0.31x = 377 - 36 = 341  ====>  x = 341%2F0.31 = 1100 mL.


Answer.  She uses 1100 mL of solution A.

Solved.

---------------------

It is a standard and typical mixture problem.

For introductory lessons covering various types of mixture word problems see
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization,  from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ml of solution B used
+x+-+300+ = ml of solution A used
覧覧覧覧覧覧
+.19%2A%28+x+-+300+%29+=+alcohol+in+solution+A%0D%0A%7B%7B%7B+.12x+ = alcohol in solution B
+377+ = alcohol in solution A and B
覧覧覧覧覧覧
+.12x+%2B+.19%2A%28+x+-+300+%29+=+377+
+.12x+%2B+.19x+-+57+=+377+
+.31x+=+434+
+x+=+1400+
And
+x+-+300+=+1400+-+300+
+x+-+300+=+1100+
She uses 1100 ml of solution A
覧覧覧覧覧覧覧覧-
Check:
+x+%2B+x+-+300+=+1100+%2B+1400+
+2x+-+300+=+2500+
+2x+=+2800+
+x+=+1400+
OK