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Let "n" be the middle of the three consecutive odd integer numbers.
Then the numbers are (n-2), n and (n+2), and their sum is
(n-2) + n + (n+2) = 3n.
Then the condition says that
3n = 4n - 13.
Simplify and solve it:
13 = 4n - 3n ====> 13 = n.
Answer. The three numbers are 11, 13 and 15.
Solved.