SOLUTION: The stage of a rocket burns 28s longer than the second stage. If the total burning time for both stages is 152 s how long does each stage burn?
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Question 1121843: The stage of a rocket burns 28s longer than the second stage. If the total burning time for both stages is 152 s how long does each stage burn? Found 2 solutions by ikleyn, josmiceli:Answer by ikleyn(52910) (Show Source):
You can put this solution on YOUR website! .
The stage of a rocket burns 28 s longer than the second stage.
If the total burning time for both stages is 152 s how long does each stage burn?
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From the condition, you have these two equations
x + y = 152 (1) (x = the first stage burning time)
x - y = 28 (2)
Add the two equations. You will get
2x = 152 + 28 = 180 ====> x = 90 seconds for the first stage.
Then y = 152 - 90 = 62 seconds for the seconf stage.
You can put this solution on YOUR website! Let = burn time in sec for 2nd stage = burn time for 1st stage
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And
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1st stage: 90 sec
2nd stage: 62 sec
