SOLUTION: a page with length 3 inches more than its width, has 80 square inches of printed area. the margins at the top and bottom are each 1 inch wide. Find the dimension of the page

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Question 1121801: a page with length 3 inches more than its width, has 80 square inches of printed area. the margins at the top and bottom are each 1 inch wide. Find the dimension of the page
Answer by ikleyn(52818) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let w be the page width, in inches.


Then its length is (w+3) inches.


The printed area has dimensions in 2 = 1 + 1 inches less. Therefore, the equation for the printed area is


(w-2)*(w+1) = 80.


w^2 -w - 82 = 0.


Solve it using the quadratic formula.


w%5B1%2C2%5D = %281+%2B-+sqrt%281%5E2+%2B4%2A82%29%29%2F2 = %281+%2B-+sqrt%28329%29%29%2F2 = %281+%2B-+18.14%29%2F2.


Only positive value of w makes sense, which is  w = %281+%2B+18.14%29%2F2 = 9.57 inches.


Answer.  The dimensions of the page are  9.57 and 12.57 inches.


Check.   (9.57-2)*(12.57-2) = 80.0 square inches.  The solution is correct.