SOLUTION: Collin is building a deck on the back of his house . He has enough lumber for the deck to be 144 square feet. The length should be 10 feet or more than its width. What should the d

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Collin is building a deck on the back of his house . He has enough lumber for the deck to be 144 square feet. The length should be 10 feet or more than its width. What should the d      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1121742: Collin is building a deck on the back of his house . He has enough lumber for the deck to be 144 square feet. The length should be 10 feet or more than its width. What should the dimensions of the deck be.
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
length(l) = width(w) +10
:
l * w + Area
:
(w+10) * w = 144
:
w^2 +10w -144 = 0
:
(w+18) * (w-8) = 0
:
w = -18 or 8
:
we reject the negative value for w
:
length is 18 feet and width is 8 feet
:
***************************************
144 is factored into its prime factors
:
2^4 * 3^2
:
possible dimensions for the deck are
:
length 18 feet and width is 8 feet
:
length 36 feet and width 4 feet
:
length 24 feet and width is 6 feet
:
length is 72 feet and width is 2 feet
:
length is 144 feet and width is 1 foot
*****************************************
: