SOLUTION: In a sample of 200 bottles at a factory, 38 had major defects. The sampling method had a margin of error of 0.02.
What is the interval estimate for the proportion that would hav
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-> SOLUTION: In a sample of 200 bottles at a factory, 38 had major defects. The sampling method had a margin of error of 0.02.
What is the interval estimate for the proportion that would hav
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Question 1121738: In a sample of 200 bottles at a factory, 38 had major defects. The sampling method had a margin of error of 0.02.
What is the interval estimate for the proportion that would have defects in the form (lower limit, upper limit) ? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! point estimate of defects is 38/200=0.19
if margin of error is 0.02, the interval is (0.17, 0.21) for proportion that have defects.
