SOLUTION: Graph: y=4/5x-7

Algebra ->  Graphs -> SOLUTION: Graph: y=4/5x-7      Log On


   



Question 112171: Graph:
y=4/5x-7

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=%284%2F5%29%2Ax-7 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=0

y=%284%2F5%29%2A%280%29-7

y=0%2F5-7 Multiply

y=-35%2F5 Add

y=-7 Reduce

So here's one point (0,-7)




Now lets find another point

Plug in x=5

y=%284%2F5%29%2A%285%29-7

y=20%2F5-7 Multiply

y=-15%2F5 Add

y=-3 Reduce

So here's another point (5,-3). Add this to our graph





Now draw a line through these points

So this is the graph of y=%284%2F5%29%2Ax-7 through the points (0,-7) and (5,-3)


So from the graph we can see that the slope is 4%2F5 (which tells us that in order to go from point to point we have to start at one point and go up 4 units and to the right 5 units to get to the next point) the y-intercept is (0,-7)and the x-intercept is (8.75,0) ,or (35%2F4,0)


We could graph this equation another way. Since b=-7 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-7).


So we have one point (0,-7)





Now since the slope is 4%2F5, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-7), we can go up 4 units



and to the right 5 units to get to our next point


Now draw a line through those points to graph y=%284%2F5%29%2Ax-7


So this is the graph of y=%284%2F5%29%2Ax-7 through the points (0,-7) and (5,-3)