Question 1121704: A basketball team won 60% of the 55 games they played.
What fraction of their games were lost?
I知 just not sure
Thank you Found 3 solutions by Theo, Alan3354, MathTherapy:Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! if they won 60% of the games the played and they played 55 games, then they won .6 * 55 = 33 games.
since they can only win or lose, then all of the games they didn't win, they lost.
therefore, they had to lose 55 - 33 = 22 games.
33 wins and 22 losses totals 55 games.
33 / 55 = .6 = 60%.
22 / 55 = .4 = 40%.
60% wins and 40% losses translates into 33 wins and 22 loses.
You can put this solution on YOUR website! A basketball team won 60% of the 55 games they played.
What fraction of their games were lost?
============
100% - 60% = 40%
You can put this solution on YOUR website! A basketball team won 60% of the 55 games they played.
What fraction of their games were lost?
I知 just not sure
Thank you
What are you unsure about?
60% of games were won, so of games were LOST.
OR
60% of games were won, and
As the team won of the games, fraction lost =
