SOLUTION: I am asked to draw the function. {{{f(x)= -((x^3)/(3)) -x^2 +3x +10 }}} I have found the max (1,11.6), min (1,-3) and y-intercept (0,10) but am not sure how to find the x-inter

Algebra ->  Rational-functions -> SOLUTION: I am asked to draw the function. {{{f(x)= -((x^3)/(3)) -x^2 +3x +10 }}} I have found the max (1,11.6), min (1,-3) and y-intercept (0,10) but am not sure how to find the x-inter      Log On


   

Question 1121521: I am asked to draw the function.
f%28x%29=+-%28%28x%5E3%29%2F%283%29%29+-x%5E2+%2B3x+%2B10+
I have found the max (1,11.6), min (1,-3) and y-intercept (0,10) but am not sure how to find the x-intercept.
Can someone please explain how to draw it without graphing on a computer?
Thanks.
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I am asked to draw the function.
f%28x%29=+-%28%28x%5E3%29%2F%283%29%29+-x%5E2+%2B3x+%2B10+
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Pick values for x, and find the f(x).
Plot the points.
Draw a curve thru them.
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Unless instructed to do so. you don't need find the x-intercept(s).

Answer by josgarithmetic(39631) About Me  (Show Source):
You can put this solution on YOUR website!
You might want to find y-axis intercept by solving for f(x)=0. That would be (0, 10).

Take first and second derivatives of f(x). The first derivative will help identifying any maximum or minimum points (where slope of f would be 0). Seeing the sign on leading term for f, you should be able to figure out which is the max and which is the min.

That was just suggested guidance, not actually the answer or solution.