SOLUTION: Find the value of $a$ so that the lines with the given equations are perpendicular. \begin{align*} y &= 2x+13 \\ 6y+ax &= 6. \end{align*}

Algebra ->  Graphs -> SOLUTION: Find the value of $a$ so that the lines with the given equations are perpendicular. \begin{align*} y &= 2x+13 \\ 6y+ax &= 6. \end{align*}      Log On


   



Question 1121470: Find the value of $a$ so that the lines with the given equations are perpendicular. \begin{align*}
y &= 2x+13 \\
6y+ax &= 6.
\end{align*}

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
y = 2x + 13 has the slope of  2.


6y +ax = 6   is the same as  y = %28-ax%2B6%29%2F6  and has the slope of  -a%2F6.


You want to have -1%2F2 = -a%2F6  (perpendicularity condition),  which leads you to


1%2F2 = a%2F6;   hence,  a = %281%2F2%29%2A6 = 3.


Answer.  a = 3.

Solved.

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