SOLUTION: Find the equation of the parabola in the form y= ax^2 + bx + c if it has the x intercepts of 3 and -6 and a y intercept of -9. Thank you :)
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-> SOLUTION: Find the equation of the parabola in the form y= ax^2 + bx + c if it has the x intercepts of 3 and -6 and a y intercept of -9. Thank you :)
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Question 1121451: Find the equation of the parabola in the form y= ax^2 + bx + c if it has the x intercepts of 3 and -6 and a y intercept of -9. Thank you :) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! for the x-intercept of 3, a factor is (x-3). For the x-intercept of -6, the factor is (x+6)
the polynomial is f(x)= a(x^2+3x-18)
When x=0, f(x)=-9
-18a=-9
a=(1/2)
f(x)=(1/2)x^2+(3/2)x-9.
