SOLUTION: Find the standard form of the parabola: x2 - 16x - 48y - 512 = 0

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Question 1121358: Find the standard form of the parabola: x2 - 16x - 48y - 512 = 0
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square, adding 64 (half the 16 squared) to both sides
x^2-16x+64-48y-512=64
(x-8)^2-576=48y, rearranging.
(1/12)(x-8)^2-12=y, dividing by 48 both sides
The vertex is at (8,-12)
Some consider the form ax^2+bx+c=0 to be standard form.
This would be y=(1/12)x^2-(3/4)x-5/9
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