SOLUTION: Find all solutions of the equation in the interval [0, 2pi). -4 cos x =-sin^2(x)+4 Write your answer in radians in terms of pi. If there is more than one solution, separate them

Algebra ->  Trigonometry-basics -> SOLUTION: Find all solutions of the equation in the interval [0, 2pi). -4 cos x =-sin^2(x)+4 Write your answer in radians in terms of pi. If there is more than one solution, separate them      Log On


   

Question 1121304: Find all solutions of the equation in the interval [0, 2pi).
-4 cos x =-sin^2(x)+4
Write your answer in radians in terms of pi.
If there is more than one solution, separate them with commas.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
-4+cos+x+=-sin%5E2%28x%29%2B4

-4cos%28x%29=-sin%5E2%28x%29%2B4
-4cos%28x%29=cos%5E2%28x%29-1%2B4
cos%5E2%28x%29%2B4cos%28x%29%2B3=0
%28cos%28x%29%2B1%29%28cos%28x%29%2B3%29=0
cos%28x%29=-1

x=pi
(Check for mistakes)








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sin^2(x)+cos^2(x)=1
sin^2(x)=1-cos^2(x)