SOLUTION: Suppose $f$ is a polynomial such that $f(0) = 47$, $f(1) = 32$, $f(2) = -13$, and $f(3)=16$. What is the sum of the coefficients of $f$?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Suppose $f$ is a polynomial such that $f(0) = 47$, $f(1) = 32$, $f(2) = -13$, and $f(3)=16$. What is the sum of the coefficients of $f$?      Log On


   

Question 1121223: Suppose $f$ is a polynomial such that $f(0) = 47$, $f(1) = 32$, $f(2) = -13$, and $f(3)=16$. What is the sum of the coefficients of $f$?
Answer by ikleyn(52933) About Me  (Show Source):
You can put this solution on YOUR website!
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The sum of coefficients of any polynomial f(x) is equal to f(1), the value of the polynomial at x= 1.


In your case the sum of coefficients of the given polynomial is equal to f(1) = 32, as it is given.


The rest of the info is irrelevant and was given with the only goal to confuse you and to direct you onto wrong way.



    //  So, they actually want to check if you know firmly the right way to solve it.

Completed and solved.