SOLUTION: ronnie has P92.00 in ones, fives and tens coins. He has 4 more P1.00 coins than P10.00 coins. the number of P5.00 coins is 2 more than 3 times the number of P10.00 coins. how many
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-> SOLUTION: ronnie has P92.00 in ones, fives and tens coins. He has 4 more P1.00 coins than P10.00 coins. the number of P5.00 coins is 2 more than 3 times the number of P10.00 coins. how many
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Question 1121177: ronnie has P92.00 in ones, fives and tens coins. He has 4 more P1.00 coins than P10.00 coins. the number of P5.00 coins is 2 more than 3 times the number of P10.00 coins. how many P5.00 coins are there? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39620) (Show Source):
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ronnie has P92.00 in ones, fives and tens coins. He has 4 more P1.00 coins than P10.00 coins. the number of P5.00 coins is 2 more than 3 times the number of P10.00 coins. how many P5.00 coins are there?
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x, P1 coins
y, P5 coins
z, P10 coins
Use equations #2 and #3 in terms of z.
Substitute for x and y in the equation #1. ------One equation in one unknown variable, z. Solve...
Let x be the number of P10 coins.
Then the number of P1 coins is (x+4), and the number of P5 coins is (3x+2).
The money equation then is
(x+4) + 5*(3x+2) + 10x = 92
x + 15x + 10x + (4 + 10) = 92
26x = 92 - 14 = 78
x = = 3.
Answer. 3 P10 coins; (3+4) = 7 P1 coins; and 3x+2 = 3*3+2 = 11 P5 coins.
Check. 3*10 + 7*1 + 11*5 = 92. ! Correct !
Solved.
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Be aware : The solution by @josgaritmetic is W R O N G, starting from his very first equation.
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