SOLUTION: initially a ship and submarine are stationary at sea level 1.78km apart. the submarine then manoeuvres to position A, 45 meters directly below its starting point. in a second manoe

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Question 1121165: initially a ship and submarine are stationary at sea level 1.78km apart. the submarine then manoeuvres to position A, 45 meters directly below its starting point. in a second manoeuvres the submarine dives a further 62 meters to position B. a find the angle of elevation of the ship from the submarine when the submarine is at position A
B find the angle of elevation of the ship from the submarine when the submarine is at position B.
c find the difference in the angles of elevation from the submarine to the ship when the submarine is at position A and B
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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nitially a ship and submarine are stationary at sea level 1.78km apart.
the submarine then maneuvers to position A, 45 meters directly below its starting point.
in a second maneuvers the submarine dives a further 62 meters to position B.
:
Change 1.78 km to 1780 meters
:
a find the angle of elevation of the ship from the submarine when the submarine is at position A
A triangle is formed by the ship, the surface point of the sub and 45' underwater point. Find the angle (A) at the sub using the tangent
tan(A) = 1780/45
A = 88.55 degrees
Find angle of elevation: 90 - 88.55 = 1.45 degrees to ship
:
b find the angle of elevation of the ship from the submarine when the submarine is at position B
Total depth at position B: 45 + 62 = 107 ft
Tan(B) = 1780/107
B = 86.56 degrees
Find the angle of elevation: 90 - 86.56 = 3.44 degrees to the ship
:
c find the difference in the angles of elevation from the submarine to the ship when the submarine is at position A and B
3.44 - 1.45 = 1.99 degree difference