SOLUTION: Can you help me solve this word problem please?: A man bought two vanilla ice cream cones, three chocolate cones, four strawberry cones, and one pistachio cone for his ten children

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Question 1121121: Can you help me solve this word problem please?: A man bought two vanilla ice cream cones, three chocolate cones, four strawberry cones, and one pistachio cone for his ten children. In how many ways can he distribute the flavors among children?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
There are two ways to interpret and solve it.

1.
There are  C%5B10%5D%5E2  ways to select two children of 10 for vanilla ice cream;

There are  C%5B8%5D%5E3  ways to select three children of remaining 8 for chocolate cones;

There are  C%5B5%5D%5E4  ways to select four children of remaining 5 for strawberry cones;

and there is just NO CHOICE (the unique selection) for this lucky one who will get the pistachio cone.


Now take the product  C%5B10%5D%5E2.C%5B8%5D%5E3.C%5B5%5D%5E4  to get your answer.

2.
It is the number of all distinguishable permutations of 10 objects, two of which are indistinguishable vanilla ice cream;


the other three are indistinguishable chocolate cones, and the other four are indistinguishable strawberry cones.


In all, there are  10%21%2F%282%21%2A3%21%2A4%21%29 such distinguishable arrangements.

Both answers coincide, for your fortune.

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On the last subject, see the lesson
    - Arranging elements of sets containing indistinguishable elements
in this site.


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Let the four flavors be represented by V, C, S, and P. The number of different ways of distributing the cones among the four children is the number of different arrangements of the letters

VVCCCSSSSP

By a well-known counting principle, that number of different ways is

%2810%21%29%2F%28%282%21%29%283%21%29%284%21%29%281%21%29%29+=+12600