SOLUTION: Suppose that a cyclist began a 377 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the sta

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Question 1121079: Suppose that a cyclist began a 377 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 6.5 hr and the car traveled 30.6 mph faster than the​ bicycle, find the average rate of each.
Found 2 solutions by josgarithmetic, solver91311:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Cyclist Speed, r
Car Speed, r+30.6

%28r%2Br%2B30.6%29%2A6.5=377
-
2r%2B30.6=377%2F6.5
highlight%28r=13.7%29, Cyclist Speed
--
Car Speed, highlight%2843.7%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the rate of the cycle, then represents the rate of the car. Since they are traveling toward each other, their combined rate is the sum of the two, or . In 6.5 hours, they traveled a combined distance of 377 miles, so their combined rate is 377 divided by 6.5, or 58 miles per hour.



Solve for , then calculate


John

My calculator said it, I believe it, that settles it