SOLUTION: Hi, I need step by step solution for this inequality: log_3^(1/2)(x) -5log_3(x) <2 Solution should be x>1/9^(1/3). My Idea was to convert all to log_3 as follows: log_3(x)/l

Algebra ->  Inequalities -> SOLUTION: Hi, I need step by step solution for this inequality: log_3^(1/2)(x) -5log_3(x) <2 Solution should be x>1/9^(1/3). My Idea was to convert all to log_3 as follows: log_3(x)/l      Log On


   



Question 1121001: Hi, I need step by step solution for this inequality: log_3^(1/2)(x) -5log_3(x) <2 Solution should be x>1/9^(1/3). My Idea was to convert all to log_3 as follows: log_3(x)/log_3(3^(1/2)) - log_3(x^5)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If 3 is the base, what is this?
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log_3^(1/2)(x)
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Use the triple {...} braces.
eg, log%283%2Cx%29
===================
log%28sqrt%283%29%2Cx%29+-+5log%283%2Cx%29+%3C+2
---
Convert to base 3:
log%283%2Cx%2F2%29+-+5log%283%2Cx%29+%3C+log%283%2C9%29
log%283%2Cx%2F2%29+-+log%283%2Cx%5E5%29+%3C+log%283%2C9%29
log%283%2C%28x%2F2%29%2Fx%5E5%29+%3C+log%283%2C9%29
%281%2F2%29%2Fx%5E4+%3C+9
1%2Fx%5E4+%3C+18
1+%3C+18x%5E4
18x%5E4+%3E+1
x%5E4+%3E+1%2F18
x+%3E+root%284%2C%281%2F18%29%29