SOLUTION: A man travels from Town A to Town B at an average speed of 4 km and from Town B to Town A at an average speed of 6km. If he takes 45 mins to complete the entire journey, find the t

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Question 1120861: A man travels from Town A to Town B at an average speed of 4 km and from Town B to Town A at an average speed of 6km. If he takes 45 mins to complete the entire journey, find the total distance traveled.
Found 2 solutions by Alan3354, greenestamps:
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
A man travels from Town A to Town B at an average speed of 4 km and from Town B to Town A at an average speed of 6km. If he takes 45 mins to complete the entire journey, find the total distance traveled.
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4 km and 6 km are distances, not speed.
If you mean km/hr:
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Find the average speed of the round trip.
Avg = 2*4*6/(4+6) = 4.8 km/hr
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RT distance = 4.8 km/hr * 0.75 hours = 3.6 km

Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!

Since the distances are the same and the speeds for the two legs are in the ratio 2:3, the amounts of time required for the two legs are in the ratio 3:2.

45 minutes divided in the ratio 3:2 means 27 minutes (9/20 hours) for the trip at 4km/hr and 18 minutes (3/10 hours) for the trip at 6km/hr.

The distance between the towns is
(4km/hr)(9/20hr) = 36/20km = 1.8km
or
(6km/hr)(3/10hr) = 18/10km = 1.8km

The total distance is then 2(1.8km) = 3.6km.