Question 1120809: two six sided dice are rolled.
a. what is the probability of the event: sum more than 1
b. what is the probability of the event: sum equal to 4 or sum greater than 11
c. what is the probability of the event: sum is not equal to 7
d. what is the probability of the event: the two dice show the same numbers when they land
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! when two six-sided dice are rolled, there are 6^2 = 36 possible events
:
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
:
a. there are 36 events with sums > 1, probability(P) = 36/36 = 1
:
b. the sums = 4 are (1,3), (2,2), (3,1), P = 3/36
the sums > 11 are (6,6), P = 1/36
P(sum is 4 or > 11) = 3/36 + 1/36 = 4/36 = 1/9
:
c. sums = 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), P = 6/36
P(sum is not = 7) = 36/36 - 6/36 = 30/36 = 5/6
:
d. dice show same numbers = (1,1), (2,2), (3,3), (4,4), (5,5), (6,6), P = 6/36
P( dice show same numbers) = 6/36 = 1/6
:
|
|
|
