SOLUTION: Find angle B where: A = 129o, a = 33 in, b = 52 in Round your answer to two decimal places. If no triangle exists, enter N into the first box.

Algebra ->  Finance -> SOLUTION: Find angle B where: A = 129o, a = 33 in, b = 52 in Round your answer to two decimal places. If no triangle exists, enter N into the first box.      Log On


   

Question 1120728: Find angle B where: A = 129o, a = 33 in, b = 52 in
Round your answer to two decimal places.
If no triangle exists, enter N into the first box.
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
angle A = 129 degrees.
a = 33
b = 52

by the law of sines:

a / sin(A) = b / sin(B)

cross multiply to get a * sin(B) = b * sin(A)

solve for sin(B) to get sin(B) = b * sin(A) / a

a = 33
b = 52
A = 129 degrees.

you get sin(B) = 52 * sin(129) / 33 = 1.224593636.

since sine can't be greater than 1, your triangle is impossible.

consequently, no triangle with those dimensions exists.