SOLUTION: Philip wants to construct a dog pen at the back of his garage. He will use the wall of the garage as one side of the pen and will construct the rest of the rectangular pen from 28

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Philip wants to construct a dog pen at the back of his garage. He will use the wall of the garage as one side of the pen and will construct the rest of the rectangular pen from 28       Log On


   

Question 1120630: Philip wants to construct a dog pen at the back of his garage. He will use the wall of the garage as one side of the pen and will construct the rest of the rectangular pen from 28 yards of fencing. What should the dimensions of the pen be if Philip wants it to have maximum area.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Draw this
The width of the fence is x
There are two widths for 2x
The rest, 28-x is the length of one side
A=x(28-x)=-x^2+28x
From calculus or vertex = -b/2a, the x value is -28/-2=14
x is 14
2x=28
Max area is 392 yds^2.