SOLUTION: Write the equation of the line passing through (–6, –3) and (–6, 1).

Algebra ->  Linear-equations -> SOLUTION: Write the equation of the line passing through (–6, –3) and (–6, 1).      Log On


   



Question 112053: Write the equation of the line passing through (–6, –3) and (–6, 1).
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Y2=1, Y1=-3, X2=-6, X1=-6.
1-(-3)=1+3=4 THIS IS THE NUMERATOR.
-6-(-6)=-6+6=0 THIS IS THE DENOMINATOR.
THE BEST EXPLANATION I HAVE IS TO PLOT THESE 2 SETS OF POINTS AND DRAW A LINE BETWEEN THEM.
DON'T KNOW WHERE YOU GET THE 3-17 ?????????
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the line equation is: y=Mx+B where M=slope & B=the y intercept.
first we need to find the slope (y2-y1)/(x2-x1)
(1+3)/(-6*6)=4/0 or this slope is undefined & is a verticle line through the point x=-6
thus the line equation is:
x=-6 & has no y intercept.