SOLUTION: Three research departments have 7,8 and 6 members, respectively. Each department is to select a delegate and an alternate to represent the department at a conference. In how

Algebra ->  Permutations -> SOLUTION: Three research departments have 7,8 and 6 members, respectively. Each department is to select a delegate and an alternate to represent the department at a conference. In how       Log On


   

Question 1120491:

Three research departments have 7,8 and 6 members, respectively. Each department is to select a delegate and an alternate to represent the department at a conference. In how many ways can this be done?





Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The first department has 7 choices for the delegate and then 6 choices for the alternate, for a total of 7*6 = 42 choices.

The second department has 8 choices for the delegate and the 7 for the alternate.

The third department has 6 choices for the delegate and then 5 choices for the alternate.

The total number of ways of selecting the delegates and alternates is the product of the numbers of ways for each of the three departments.

You can do the arithmetic.