SOLUTION: Sergio , Tyrone , Jim , and Dawn have all been invited to a dinner party. They arrive randomly and each person arrives at a different time. a. In how many ways can they​ a

Algebra ->  Probability-and-statistics -> SOLUTION: Sergio , Tyrone , Jim , and Dawn have all been invited to a dinner party. They arrive randomly and each person arrives at a different time. a. In how many ways can they​ a      Log On


   

Question 1120447: Sergio , Tyrone , Jim , and Dawn have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a. In how many ways can they​ arrive?
b. In how many ways can Sergio arrive first and Dawn ​last?
c. Find the probability that Sergio will arrive first and Dawn last.
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


(a) 4! = 24 ways. Any of the 4 first; then any of the remaining 3 next; then either of the other 2, then the last 1.

(b) Either Tyrone or Jim can arrive second and then the other arrives third: 2 ways.

(c) The answer to (b) divided by the answer to (a); 2 ways for that to happen, out of a total of 24 different possible ways: 2/24 = 1/12.