SOLUTION: Factor: 9(p−1)+(p−1)^2
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Question 1120419
:
Factor: 9(p−1)+(p−1)^2
Found 2 solutions by
Boreal, MathTherapy
:
Answer by
Boreal(15235)
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9(p−1)+(p−1)^2
That is (p-1)(9+p-1)=(p-1)(p+8)
check by foiling and factoring
9p-9+p^2-2p+1
This is p^2+7p-8=(p+8)(p-1)
Answer by
MathTherapy(10552)
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Factor: 9(p−1)+(p−1)^2
9(p - 1) + (p - 1)(p - 1)
(p - 1)[9 + (p - 1)]