| 
 
 
| Question 1120396:  n a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean score of 281 with a standard deviation of 34.4. Possible test scores could range from 0 to 500.  Assume that the scores are normally distributed.
 Find the probability that a student had a score between 250 and 305.
 Answer by amarjeeth123(570)
      (Show Source): 
You can put this solution on YOUR website! Mean score=µ=281 Standard deviation=σ=34.4
 Score1=x1=250
 Score2=x2=305
 z-score z1=(x1- µ)/ σ=(250-281)/34.4=-31/34.4=-0.9011
 z-score z2=(x2- µ)/ σ=(305-281)/34.4=24/34.4=0.6976
 The probability for the first z-score from excel is =NORMDIST(250,281,34.4,TRUE)=0.183751
 The probability for the second z-score from excel is =NORMDIST(305,281,34.4,TRUE)= 0.75731
 Required probability=0.75731-0.183751=0.573559
 
 | 
  
 | 
 |