You can put this solution on YOUR website! Find the slope of the stright line which is both tangent
and normal to the curve 4x^3=27y^2
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4x^3=27y^2
12x^2dx = 54ydy
dy/dx = 2x^2/9y
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Slope of tangent = 2x^2/9y
Slope of normal = -9y/2x^2