SOLUTION: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cor

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Question 1120183: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture?
Found 3 solutions by josgarithmetic, MathTherapy, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
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x of 16% protein
320-x of the 8% protein


16x%2B8%28320-x%29=11%2A320

Solve and then find 320-x...

Answer by MathTherapy(10552) About Me  (Show Source):
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Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture?
Let the amount of protein in CORNMEAL be E

Then amount of protein in soybean = 320 - E

We then get: .08E + .16(320 - E) = .11(320)

Solve this for E, the amount of protein in cornmeal, which is what was asked for.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Here is a quick way to solve mixture problems like this involving must two ingredients.

See if it makes sense to you.... You will get the answer in a fraction of the time required for the formal algebraic solution shown by the other tutors.

(1) 11% is 3/8 of the way from 8% to 16%.
(2) Therefore 3/8 of the mixture must be the 16% ingredient.
Answer: 3/8 of the mixture -- 3/8 of 320 pounds = 120 pounds -- is the 16% protein soybean meal; the other 5/8 of the mixture -- the other 200 pounds -- is the 8% protein cornmeal.