SOLUTION: A box contains nickels, dimes and pennies worth $8.40. The number of dimes is six less than twice the number of pennies and there is an equal number of dimes and nickels. How many
Question 1120159: A box contains nickels, dimes and pennies worth $8.40. The number of dimes is six less than twice the number of pennies and there is an equal number of dimes and nickels. How many nickels are there in the box? Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! A box contains nickels, dimes and pennies worth $8.40. The number of dimes is six less than twice the number of pennies and there is an equal number of dimes and nickels. How many nickels are there in the box?
Let number of nickels be N, and number of pennies, P
Then number of dimes also = N
We also get: Number of dimes, or
We now get:
.1N + .2N + .01N + .06 = 16.8 ------- Multiplying by LCD, 2
.31N = 16.74
Number of nickels, or
You can put this solution on YOUR website! .
This problem is a typical example to solve using ONE UNKNOWN and ONE EQUATION, as the tutor @MathTherapy did.
The way @gosgarithmetic uses is the way to nowhere.