SOLUTION: Solve the equation in the interval (0 degrees, 360 degrees) sin^2 theta-sin theta-12=0

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Question 1120084: Solve the equation in the interval (0 degrees, 360 degrees)
sin^2 theta-sin theta-12=0
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52852) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the equation in the interval (0 degrees, 360 degrees)
sin^2 theta-sin theta-12=0
~~~~~~~~~~~~~~~

This equation has no real solutions.

See the plot below




Plot  y = sin%5E2%28x%29-sin%28x%29  (red)  and  y = 12  (green)  on the interval  [0,2pi).



Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


Did you type the equation correctly?

The maximum value of sin^2 theta is 1; the maximum value of |sin theta| is 1.

The maximum value of sin^2 theta - sin theta is 1+1 = 2.

Obviously the equation has no solutions.