SOLUTION: Joey has 24 coins in his pocket. The coins are all nickels and dimes. The total value of the coins is $1.85. How many dimes does Joey have?

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Question 1120064: Joey has 24 coins in his pocket. The coins are all nickels and dimes. The total value of the coins is $1.85. How many dimes does Joey have?
Answer by ikleyn(52770) About Me  (Show Source):
You can put this solution on YOUR website!
.
One line solution

    %28185+-+24%2A5%29%2F5 = 13 dimes.


    The rest 24 - 13 = 11 are nickels.


    Check.  11*5 + 13*10 = 185 cents.   ! Correct !


    Answer.  13 dimes, 11 nickels.


Explanation to the solution

Let assume that all 24 coins are nickels.  Then their total value would be 5*24 = 120 cents.


But the real value is 185, and the difference is  1805- 120 = 65 cents.   

    Notice, this difference is the NUMERATOR in my one-line solution.


Surely, you understand that the cause of this difference lies in the fact that we counted some dimes as nickels.


Now let's replace nickels by dimes. At each replacement, we decrease the difference in 5 cents,

so the total number of replacements is  the ratio  65%2F%2810-5%29 = 5 cents.


     Notice, this difference  10-5 = 5 cents is the DENOMINATOR  in my one-line solution.


Thus the ratio  NUM%2FDEN = 65%2F5 = 13  is exactly the number of dimes in the collection.


This completes the explanation.

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So, you are explained how to solve the problem in one line.

Also, you just learned this LOGICAL method on how to solve it.

In the future, you can use EITHER of these two methods.
They both are classic methods for solving this type of coin problems.