SOLUTION: A varies partly as B and partly C. When A=4, B=2 and C=-2, and when A=3, B=3 and C=1.5. What is the value of C when A=0.5 and B=2.7?

Algebra ->  Proportions -> SOLUTION: A varies partly as B and partly C. When A=4, B=2 and C=-2, and when A=3, B=3 and C=1.5. What is the value of C when A=0.5 and B=2.7?      Log On


   

Question 1120060: A varies partly as B and partly C. When A=4, B=2 and C=-2, and when A=3, B=3 and C=1.5. What is the value of C when A=0.5 and B=2.7?
Answer by solver91311(24713) About Me  (Show Source):
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A partly varies directly as B and partly varies directly as C. The qualifier "directly" is assumed because it was not stated, but it is always best to specifically state the nature of the variation, i.e. direct or inverse.



With the given initial conditions:





Solve the 2X2 system for the values of and

Then substitute the now known values of and and the new values for A and B into:



And then solve for C.


John

My calculator said it, I believe it, that settles it