SOLUTION: Lucas is 9 years older than three times his son’s age. In 14 years, the age of Lucas will be 6 years more than twice his son’s age. Find their present ages.

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Question 1120047: Lucas is 9 years older than three times his son’s age. In 14 years, the age of Lucas will be 6 years more than twice his son’s age. Find their present ages.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
L = 3y + 9               (1)
L+14 = 2*(y+14) + 6.     (2)


Substitute (1) into (2). You will get


(3y + 9) + 14 = 2*(y+14) + 6

3y + 23 = 2y + 28 + 6

y = 28 + 6 - 23 = 11.


Answer.  The son is 11 years old.  The father (=Lucas) is 3*11 + 9 = 42 years old.

Solved.

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Be aware :   The system written by @josgarithmetic

system%28L=3y%2B9%2CL%2B14=2y%2B6%29

is   I N C O R R E C T.