Question 1119979: A manufacturer of window frames knows from past experience that 20 per cent of the
production will have some type of minor defect that will require adjustment. Suppose 40
windows are selected at random:
i. How many window frames would you expect to have minor defects?
ii. What is the probability that more than 4 window frames will need minor adjustments?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A manufacturer of window frames knows from past experience that 20 per cent of the production will have some type of minor defect that will require adjustment. Suppose 40 windows are selected at random:
i. How many window frames would you expect to have minor defects?
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Binomial Problem with p = 0.2, n = 40
mean = n*p = 0.2*40 = 8
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ii. What is the probability that more than 4 window frames will need minor adjustments?
P(5<= x <=40) = 1-binomcdf(40,0.2,4) = 0.9240
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Cheers,
Stan H.
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