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Question 1119930: what is the least number which must be subtracted from 9600 so that the remaining number becomes divisible by 78
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! 9600 / 78 = 123 plus a remainder, because the answer is not an integer.
the remainder is 9600 - 78 * 123 = 6.
subtract 6 from 9600 and divide that by 78 and the remainder will be equal to 0.
9600 - 6 = 9594.
9594 / 78 = 123 with a remainder of 0.
the remainder is equal to 0 because the answer of 123 is an integer.
since the remainder is equal to 0, 9594 is divisible by 78.
the smallest number you can subtract from 9600 so that the result is divisible by 78 is 6.
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