SOLUTION: Use the position function s(t)=−16t^2+v0t+s0 v0=initial velocity,s0=initial position,t=time to answer the following question. You throw a ball straight up from a

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Use the position function s(t)=−16t^2+v0t+s0 v0=initial velocity,s0=initial position,t=time to answer the following question. You throw a ball straight up from a       Log On


   

Question 1119892: Use the position function
s(t)=−16t^2+v0t+s0
v0=initial velocity,s0=initial position,t=time
to answer the following question.
You throw a ball straight up from a rooftop 179 feet high with an initial velocity of 64 feet per second. During which time period will the ball's height exceed that of the rooftop?
Answer by rapture1965(18) About Me  (Show Source):
You can put this solution on YOUR website!
Let s(t) = 0

s_0 = 179 feet

Let v_0 = 64 feet per second

After plugging everything above into the quadratic equation,

we end up with 0 = -16t^2 + 64t + 179.

I will let you solve for t.

I assume that you know how to solve quadratic equations considering the fact

that you are asking this level of math.

Otherwise, you would not be asking this question.

So, solve 0 = -16t^2 + 64t + 179 for t.

Reject the negative answer.

Can you finish?