SOLUTION: An object moves along a straight path at a speed v(t) = 4t^2 + 3t + 2 in m/s, where t = time in seconds. Find the distance travelled after 4 seconds.
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Question 1119870: An object moves along a straight path at a speed v(t) = 4t^2 + 3t + 2 in m/s, where t = time in seconds. Find the distance travelled after 4 seconds. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An object moves along a straight path at a speed v(t) = 4t^2 + 3t + 2 in m/s, where t = time in seconds. Find the distance travelled after 4 seconds.
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v(t) = ds/st, the 1st derivative of position.
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INT(v(t)) = s(t) = 4t^3/3 + 3t^2/2 + 2t + C
s(4) = 256/3 + 48/3 + 8
s(4) = 304/3 + 8 = 328/3 meters --- Note: the C is canceled by s(0) = 0
