SOLUTION: Hi I am trying to figure out how to solve this equation: 3x = 6y = 0 x = 2/3 I can either solve it by substitution or additon. What I think should be done is to first substit

Algebra ->  Expressions-with-variables -> SOLUTION: Hi I am trying to figure out how to solve this equation: 3x = 6y = 0 x = 2/3 I can either solve it by substitution or additon. What I think should be done is to first substit      Log On


   



Question 111983: Hi I am trying to figure out how to solve this equation:
3x = 6y = 0
x = 2/3
I can either solve it by substitution or additon.
What I think should be done is to first substitute the x=2/3 into the first problem.
So, now I have 3 and 2/3 = 6y= 0
then I can make the 3 and 2/3 into an improper fraction so I now have
11/3 + 6=0
If I subtract the 11/3 from both sides I then have
6y= -11/3
The 11/3 is also a fraction 3.6 and repeating.
If I divide by 6 to isolate the y I then have
y= -0.6
Is there a better way to approach this problem so I don't get stuck with a negative decimal as I will still have to go back in and replace the y with the
-0.6
If I do the problem like I showed then I come up with x = - 1.2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
You have two equal signs in the 1st equation.
Should you?
Cheers,
Stan H.