SOLUTION: If I'm using an 8-litre container in which I wish to mix Sodium Hypochlorite(SH) at 12% with water to give me a 1% mix. How much sodium Hypochlorite(SH) would I need to add?
My th
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Question 1119792: If I'm using an 8-litre container in which I wish to mix Sodium Hypochlorite(SH) at 12% with water to give me a 1% mix. How much sodium Hypochlorite(SH) would I need to add?
My thinking is 80ml because 8 litres is 8000ml and 1% of 8000 is 80. Do I also need to take into consideration the strength of the Sodium Hypochlorite as in if the (SH) was a 10% strength that would give 1% but with it being 12% would that be a 1.2% mix? so is this a variable I have to take into consideration and if so how would I adjust depending on increased strengths of (SH)
Thank you, hope it's not too long-winded.
Regards
Mark Found 3 solutions by Alan3354, greenestamps, josgarithmetic:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! If I'm using an 8-litre container in which I wish to mix Sodium Hypochlorite(SH) at 12% with water to give me a 1% mix. How much sodium Hypochlorite(SH) would I need to add?
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You're right, the 8000 ml of solution would have 80 ml of SH.
80 ml of 12% --> 80/0.12 = 666.67 of the 12% and 8000 - 666.67 ml of water
Your method of solution is fine; and you definitely need to consider the percentage of the original solution in finding the answer.
The final mixture is to be 1% SH; 1% of 8000ml is 80ml. So you need 80ml of SH in the final mixture.
If x is the number of ml of the 12% solution you use, then the amount of SH is .12x. So you need to have
or 666 2/3 ml
You want to use 666 2/3 ml of the original solution and 8000 - 666 2/3 = 7333 1/3 ml of water to get the desired mixture.
And here is a common sense solution method you can use in a problem like this, whren you are diluting a given solution with pure water.
The concentration of the final mixture is 1/12 that of the solution you started with. That means 1/12 of the mixture must be what you started with, and 11/12 must be the water you added.
1/12 of 8000ml = 666 2/3 ml of the original solution;
11/12 of 8000ml = 7333 1/3 ml of water
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