Question 1119759: On a table in a doctor’s office are five Motor Trend magazines, six Parenting magazines, and three Sports Illustrated magazines. If a patient randomly selects three magazines, determine the probability that
a. three Motor Trend magazines are selected.
b. two Parenting magazines and one Sports Illustrated magazine are selected.
c. no Parenting magazine is selected.
d. at least one Parenting magazine is selected
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 14 magazines
(5/14)(4/13)(3/12)=0.0275 ANSWER a
three ways this can happen, PPS PSP SPP
probability of one of these is (6/14)(5/13)(3/12)--the others will have the same denominator and the same numerator, but the order in the numerator is different, which doesn't matter
That probability is 0.0412, so the overall probability is three times that or 0.1236 ANSWER b
No parenting means only of the others are chosen or (8/14)*(7/13)(6/12)=0.1538 ANSWER c
At least one parenting would be the complement or 0.8462 ANSWER d
|
|
|
