Question 1119753: A hawk drops its prey from a certain height above the ground. The height, h meters, of the prey can be modeled by h = 4 + 11t - 3t^2, where t is the time in seconds after it is dropped by the hawk.
(i) At what height above the ground does the hawk drop its prey?
(ii) At what time will the prey fall onto the ground?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A hawk drops its prey from a certain height above the ground. The height, h meters, of the prey can be modeled by h = 4 + 11t - 3t^2, where t is the time in seconds after it is dropped by the hawk.
(i) At what height above the ground does the hawk drop its prey?
At t=0, h = 4 meters.
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(ii) At what time will the prey fall onto the ground?
When h = 0
4 + 11t - 3t^2 = 0
3t^2 - 11t - 4 = 0
(3t + 1)*(t - 4) = 0
t = 4 seconds
Ignore the negative "solution"
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