SOLUTION: Find the coordinates of the vertex for the parabola defined by the given quadratic function. f(x) = -x2 + 12x + 4

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Question 1119704: Find the coordinates of the vertex for the parabola defined by the given quadratic function.
f(x) = -x2 + 12x + 4
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
-x^2+12x+4=f(x)
vertex x point is -b/2a; a=-1, b=12, so vertex has x value of 6
f(6)=-36+72+4=40
(6, 40)
graph%28300%2C300%2C-10%2C10%2C-30%2C50%2C-x%5E2%2B12x%2B4%29