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Question 1119679: My doubt is show that in matrix [1 a a^2-bc]
[1 b b^2-ac] = 0.
[1 c c^2-ab]
Answer by ikleyn(52835)   (Show Source):
You can put this solution on YOUR website! .
My doubt is show that in matrix [1 a a^2-bc]
[1 b b^2-ac] = 0.
[1 c c^2-ab]
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Based on your post, I only can guess what do you need.
If you need to calculate the determinant, apply co-factoring the determinant along the first column.
See the lesson
- Co-factoring the determinant of a 3x3 matrix
in this site, where co-factoring along the first row was described.
Co-factoring along the first column works in the same way.
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