SOLUTION: An airplane flying into a headwind travels the 2080-mile flying distance between two cities in 5 hours and 12 minutes. On the return flight, the airplane travels this distance in 4

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: An airplane flying into a headwind travels the 2080-mile flying distance between two cities in 5 hours and 12 minutes. On the return flight, the airplane travels this distance in 4      Log On


   



Question 1119624: An airplane flying into a headwind travels the 2080-mile flying distance between two cities in 5 hours and 12 minutes. On the return flight, the airplane travels this distance in 4 hours. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.
AIRSPEED:_____ (mi/h)
WINDSPEED:______(mi/h)

Found 3 solutions by Alan3354, ikleyn, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
AIRSPEED:_____ (mi/h)
WINDSPEED:______(mi/h)
===================
Do NOT enter those.

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
Hey, let me explain you something . . .

When you post the problem with this addition

    AIRSPEED:---------------(mi/h)
    WINDSPEED:--------------(mi/h)

we,  the tutors,  read it  (as every reasonable person will read it)  in this way:

     I, the author of this post, do not need the solution.
     I do not need the steps. I don't want learn the method.
     I want only the numbers in the answer.

OK,  so if you know the method,  then why don't you calculate the numbers on your own ?

We,  the tutors,  are not the machines to calculate for you,  or instead of you,  or substitute you in doing YOUR job.

Our mission  (function)  in this forum is totally different:  it is to  TEACH  the students.

If,  in opposite,  YOU NEED THE STEPS,  then do not place these irritating lines in your post.


I assume that every reasonable person understands it  (must understand it)  without these explanations.


In other words,  every reasonable person must understand what he  (or she)  is doing.



Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
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into a headwind travels the 2080-mile flying distance between two cities in 5 hours and 12 minutes. On the return flight, the airplane travels this distance in 4 hours. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.
--------------------------------------------------------------------

r, speed of plane if no wind
w, speed of wind
12 minutes is 0.2 hour or 1%2F5 hour.
RATE            TIME           DISTANCE

r-w             5.2            2080
r+w             4              2080

RT=D
;
R=D%2FT
;

system%28r-w=2080%2F5.2%2Cr%2Bw=2080%2F4%29
You should be able to understand the information organized as shown and to continue from this system of equations.