SOLUTION: A mother 41 years old and her daughter is 9 years old. In how many years will the mother be three times as old as her daughter?
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Question 1119547
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A mother 41 years old and her daughter is 9 years old. In how many years will the mother be three times as old as her daughter?
Answer by
Theo(13342)
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the mother is 41 when her daughter is 9.
in how many years will the mother be three times as sold as her daughter.
let x be the number of years.
the formula is 41 + x = 3 * (9 + x).
simplify to get 41 + x = 27 + 3x
subtract 27 from both sides of the equation and subtract x from both sides of the equation to get 41 - 27 = 3x - x
simplify to get 14 = 2x
solve for x to get x = 7.
if this is correct, then 41 + 7 = 3 * (9 + 7).
simplify to get 48 = 3 * 16.
since 3 * 16 = 48, this equation is true and the solution is confirmed to be correct.
the mother is 48 in 7 years.
the daughter is 16 in 7 years.
48 is equal to 3 * 16.
the solution is 7 years.