SOLUTION: Using the graph of y=-x^2+4x+5. what is the equation of the line of symmetry for this graph?

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Question 111950: Using the graph of y=-x^2+4x+5. what is the equation of the line of symmetry for this graph?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Y=-X^2+4X+5
Y=-(X^2-4X-5) NOW COMPLETE THE SQUARE SO YOU HAVE THE EQUATION IN THE FORM:
Y=(X-H)^2+K WHERE H IS THE SYMMETRY & K IS THE Y VERTEX VALUE.
Y=-(X^2-4X+4)-5-4
Y=-(X-2)^2-9
Y=-(X-[+2])^2-9 [+2] IS THE LINE OF SYMMETRY.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-x%5E2+%2B4x+%2B5%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -x^2 +4x +5).