SOLUTION: A quadratic equation is provided below, where r and s are constants. What are the solutions for x?
rx^2=(1/s)x+3
(a)x=(1/2sr)+-(squarerootof[(1/s^2)+3])/2r
(b)x=(1/2sr)+-(squ
Algebra ->
Radicals
-> SOLUTION: A quadratic equation is provided below, where r and s are constants. What are the solutions for x?
rx^2=(1/s)x+3
(a)x=(1/2sr)+-(squarerootof[(1/s^2)+3])/2r
(b)x=(1/2sr)+-(squ
Log On
Question 1119261: A quadratic equation is provided below, where r and s are constants. What are the solutions for x?
rx^2=(1/s)x+3
(a)x=(1/2sr)+-(squarerootof[(1/s^2)+3])/2r
(b)x=(1/2sr)+-(squarerootof[(-1/s^2)-12r])/2sr
(c)x=(s/2r)+-(squarerootof[(-1/s^2)-12r])/2r
(d)x=(s/2r)+-(sqarerootof[(s^2-12sr)])/2sr Answer by josgarithmetic(39617) (Show Source):